PHYSICS ESSAY
More coming!
Just keep Refreshing steady
(1)
Workdone = 1/2Fe
= 1/2 ื 40 ื 1/100
= 1/5 = 0.2J
(2a)
(i)Navigation satellites e.g global position system - GPS
(ii) Communication satellites eg ANIK
(2b)
V = 2πR/T
For every second,
Speed, V = 2πR
V = 2 ื 22/7 ื 6300
V = 39,600km/s
(3)
V=u cosθ -gt
V=40*cos30-10*1
V=34.64-10
V=24.64m/s
(5a)
Wave particles duality is the concept in quantum mechanics that every particles or quantum entitle may be described as either a particle or wave.
(5b)
λ=h/MV
4.2*10^-นน=h/1.6*10^-ฒณ
h=4.2*10^-นน * 1.6*10^-ฒณ
h=6.72*10^-ณ⁴
(6)
(i)reflection
(ii)refraction
(iii)diffraction
(7a)
Fiber optics work on the principle of total internal reflection.
(7bi)
Core: This is the light transmission area of the fiber, either glass or plastic.
(7bii)
cladding is made of a material with a slightly lower index of refraction than the core
(8ai)
Hooke's law states that the extension e produced by an elastic material is directly proportional to the applied force provided the elastic unit is not exceeded.
(8aii)
(i) Given extension, e = I2 - I1 = 0.75 - 0.20 = 0.55m
Force applied, Fe = (1.95 - 0.30) ื 10
= 1.65 ื 10 = 16.5N
Force constant , K = F/R = 16.5/0.55 = 30N/m
(ii) Using F = K (I1 - Io)
m1g = K ( I1 - Io)
= 0.30 ื 10 = 30(0.20 - Io)
= 0.10 = 0.20 - Io
Io = 0.20 - 0.10
Io = 0.10m
Length of spring when it was unloaded = 0.10m
(8bi)
Diffusion is the net movement of particles from a region of higher concentration to a region of lower concentration.
(8bii)
(i) Temperature
(ii) Size of particles
(8biii)
Rate of diffusion is inversely proportional to the square root of density under given conditions of temperature and pressure. ie R ∝ 1/√d
(8c)
T = circumference of the orbit/orbit velocity
T = 2πR/v
But V = √GM/R
T = 2π√Rณ/GM
(11ai)
Root measurement value of an alternating current is the value of A.C current that has the same heating affect as a D.C current
(11aii)
Impedance is the affective resistance of an electric circuit arising from the combined affects of ohmic resistance and reactance .( ie resistors, indicators and capacitors)
(11b)
Current in circuit , I = 60/120 = 0.5A
Voltage across device , Vr = 120V
Voltage across capacitor , Vc = √Vฒ - Vr
Vc = √240ฒ - 120ฒ
Vc = 207.846V
Ic = I = 0.5
Xc = Vc/Ic = 207.846/0.5 = 415.7Ω
Capacitance, C = Xc/2πf = 415.7/2*3.142*50 = 1.323F
(11ci)
The capacitance of a capacitor is the ratio of the amount of charge on its plates to the potential difference between them. ie C = ∑/V
(11cii)
(i) Charge in both capacitors are the same
∑1 = Q2
ie C1V1 = C2V2 .........(1)
Total capacitance ,C = C1C2/C1+C2
C = C2/1+C2/C1 = C2/1+V/V2
C = C2V2/V1+V2 = C2V2/2
C= 1/2C2V2
(ii)Voltage across, V1 = (C2/C1+C2) ื V
V1 = (C1/C1+C2) ื V
But C1/C2 = d2/d1 = 5/2
V1 = (1/(5/2+1)) ื 2 = 2/7 ื2 = 4/7Volts
Voltage across, C2 : V2 = 2-4/7 = 10/7volts