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Author Topic: WAEC GENERAL MATHEMATICS EASY AND OBJECTIVE 2021/2022 ANSWERS  (Read 1728 times)

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Offline NORTOLA

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WAEC GENERAL MATHEMATICS EASY AND OBJECTIVE 2021/2022 ANSWERS
« on: September 19, 2021, 12:01:44 pm »
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Offline NORTOLA

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Offline NORTOLA

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(1a)

Given A={2,4,6,8,}
B={3,6,9,12,}
C={1,2,3,6}
U= {1,2,3,4,5,6,7,8,9,10}

A = {1,3,5,7,9}
B = {1,2,4,5,7,8,10}
C = {4,5,7,8,9,10}
AnBnC = {5, 7}

(1b)
Cost of each premiere ticket = $18.50
At bulk purchase, cost of each = $80.00/50 = $16.00

Amount saved = $18.50 $16.00
=$2.50
=======================================

(2ai)
P = (rk/Q ms)⅔
P^3/2 = rk/Q ms
rk/Q = P^3/2 + ms
Q= rk/P^3/2 + ms

(2aii)
When P =3, m=15, s=0.2, k=4 and r=10
Q = rk/p^3/2 + ms = 10(4)/(3)^3/2 + (15)(0.2)
= 40/8.196 = 4.88(1dp)

(2b)
x + 2y/5 = x 2y
Divide both sides by y
X/y + 2/5 = x/y 2
Cross multiply
5(x/y) 10 = x/y + 2
5(x/y) x/y = 2 + 10
4x/y = 12
X/y = 3
X : y = 3 : 1
=======================================

(3a)
Diagram
CBD = CDB (base angles an scales D)
BCD+CBD+CDB=180 (Sum of < in a D)
2CDB+BCD=180
2CDB+108=180
2CDB=180-108=72
CDB=72/2=36
BDE=90(Angle in semi circle)
CDE=CDB+BDE
=36+90
=126

(3b)
(Cosx) Sinx given
(Sinx) + Cosx
Using Pythagoras theory thrid side of triangle
y= 1+√3
y= 1+ 3=4
y=√4=2
(Cosx) sinx/(sinx) + cosx

(1/2) √3/2/
(√3/2) + 1/2 = 1/4 √3/2 = 1-2√3/4
3/4+1/2 = 3+2/4
=1-2√3/4 * 4/5
=1-2√3/5
=======================================

(4a)
Total Surface Area = 224πcm
r:l = 2:5
r/l = 2/5
Cross multiply
2l/2 = 5r/2
L = 5r / 2
Total surface = πrl + πr
= πr (l + r)
24π/π = πr (5r/2 + r )/ π
224 = 5r/2 + r/1
L.c.m = 2
448 = 5r + 2r
448 / 7= 7r/7
r = 64
r = √64 = 8cm
L = 5*8/2 = 20cm

(4b)
Volume = 1/2πrh
= 1/3 * 22/7 * 8 * 8 * 18.33
= 1228.98cm
L = h + r
20 = h + 8
400 64 = h
h = 336
h = √ 336
h = 18.33cm
=======================================

(5a)
Total income = 32+m+25+40+28+45
=170+m
PR()=m/170+m = 0.15/1
M=0.15(170+m)
M=25.5+0.15m
0.85m/0.85=25.5/0.85
M=30

(5b)
Total outcome = 170 + 30 = 200

(5c)
PR(even numbers) = 30+40+50/200
=115/200 = 23/40
=======================================

(7a)
Diagram

Using Pythagoras theorem, l=48 + 14
l=2304 + 196
l=2500
l=√2500
l=50m
Area of Cone(Curved) =πrl
Area of hemisphere=2πr
Total area of structure =πrl + 2πr
=πr(l + 2r)
=22/7 * 14 [50 + 2(14)]
=22/7 * 14 * 78
=3432cm
~3430cm (3 S.F)

(7b)
let the percentage of Musa be x
Let the percentage of sesay be y
x + y=100 -1
(x 5)=2(y 5)
x 5=2y 10
x 2y=-5 -2
Equ (1) minus equ (2)
y (-2y)=100 (-5)
3y=105
y=105/3
y=35
Sesays present age is 35years
=======================================

(8a)
Let Ms Maureens Income = Nx
1/4x = shopping mall
1/3x = at an open market

Hence shopping mall and open market = 1/4x + 1/3x
= 3x + 4x/12 = 7/12x

Hence the remaining amount
= X-7/12x = 12x-7x/12 =5x/12

Then 2/5(5x/12) = mechanic workshop
= 2x/12 = x/6
Amount left = N225,000
Total expenses
= 7/12x + X/6 + 225000
= Nx

7x+2x+2,700,000/12 =Nx
9x + 2,700,000 = 12x
2,700,000 = 12x 9x
2,700,000/3 = 3x/3
X = N900,000

(ii) Amount spent on open market = 1/3X
= 1/3 900,000
= N300,000

(8b)
T3 = a + 2d = 4m 2n
T9 = a + 8d = 2m 8n
-6d = 4m 2m 2n + 8n
-6d = 2m + 6n
-6d/-6 = 2m+6n/-6
d = -m/3 n
d = -1/3m n
=======================================

(9a)
Draw the triangle

(9b)
(i)Using cosine formulae
q = x + y 2xycosQ
q = 9 + 5 295cos90
q = 81 + 25 90 0
q = 106
q = square root 106
q = 10.30 = 10km/h
Distance = 10 2 = 20km

(ii)
Using sine formula
y/sin Y = q/sin Q
5/sin Y = 10.30/sin 90
Sin Y = 5 sin90/10.30
Sin Y = 5 1/10.30
Sin Y = 0.4854
Y = sin‐(0.4854), Y = 29.04

Bearing of cyclist X from y
= 90 + 19.96
= 109.96 = 110

(9c)
Speed = 20/4, average speed = 5km/h

(12a)
BCD=ABC=40(alternate D)

DDE=2*BCD(<at centre = twice < at circle)

DDE = 2*40 = 80
OD3=OED(base < of I sealed D ODE)
ODE + OED + DOE= 180(sum of < is in D)
2ODE+DOE=180
2ODE+80=180
2ODE+180=180
2ODE+100
ODE+100/2=50

(12bi)
Digram

(12bii)
Area of parallelogram = absin
=5*7*sin125
=35*sin55
=35*0.8192
=28.67
=28.7cm(1dp)

(12c)
Given x=1/2(1-√2)
2x-2x=2[1/2(1-√2]-2(1/2(1-√2)}
=2[1-2√2+2/4]-(1-√2)
=(3-2√2/2)-(1-√2)
=3-2√2-2+2√2/2=1/2

Offline NORTOLA

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Because of pictures and other things used this website and pin to write the general mathematics examking pin is 4822

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This is wrong

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Please Sir we need maths obj answers

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Totally wrong

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1-10 CBCADABBCD
31-40 CADACBAABC
41-50 ABAADADBBB
Passino

Offline menegbobakel

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MATHS OBJ
1CBCADABBCD
11BCBADCCABC
21CDCAAADACD
31CADACBAABC
41ABAADADBBB

 

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