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Author Topic: Neco practical biology answer 2021/2022  (Read 547 times)

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Offline NORTOLA

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Neco practical biology answer 2021/2022
« on: July 22, 2021, 07:18:56 am »
biology practical 2021/2022 answers
1ai)
A- Atlas Vertebra
B- Thoracic Vertebra
C- Scapula
D- Lumbar Vertebra
(1aii)
A- Neck Region.
B- Chest Region.
C- Shoulder Region.
D- Upper Abdomen.
(1aiii)
Tabulate
Under Specimen A
(1) It has short neural Spine.
(2) Vertebrabateria Canal is Present.
Under Specimen D
(1) It has board and neural Spine.
(2) Vertebrabateria Canal is Present.
(1aiv)
(1) They both have neural canal.
(2) They both possess centrum.
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
(2ai)
I - spirogyra
J - Okro fruit
K - mango fruit
L - Tick
M - Bean weevil
(2aii)
(i)their bodies are characterised by multicellular filaments
(ii)it is an unbranched, filamentous green algae occuring in stagnant water
(2bi)
Tabulate
-Under specimen J-
(i)seed are small
(ii)many seeded
(iii)anile placentation
-Under specimen K-
(i)seed in large
(ii)one seeded
(iii)Basal placentation
(2bii)
L - class arachnid
M - class insect
(2biii)
L; cause stress in animals affected by bites, blood losses that can lead to anemia and even death
M; they make holes in the plants to oviposition the causing directed and indirect damage
(2ci)
Diagram of specimen K
(2cii)
Tabulate
-Under specimen L-
(i)pear shaped body
(ii)approximately 3 to 5 mm in length to age, species
-Under specimen M-
(i)general compact and oral in shape
(ii)size range from 1 to 22mm

Offline NORTOLA

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Re: Neco practical biology answer 2021/2022
« Reply #1 on: July 22, 2021, 07:30:41 am »
1ai)
A- Atlas Vertebra
B- Thoracic Vertebra
C- Scapula
D- Lumbar Vertebra

(1aii)
A- Neck Region.
B- Chest Region.
C- Shoulder Region.
D- Upper Abdomen.

(1aiii)
Tabulate
Under Specimen A
(i) It has short neural Spine.
(ii) Vertebrabateria Canal is Present.

Under Specimen D
(i) It has board and neural Spine.
(ii) Vertebrabateria Canal is Present.

(1aiv)
(i) They both have neural canal.
(ii) They both possess centrum.

(1b)
Diagram of specimen C


(1ci)
E - pooter
F - sweep net
G - tridax fruit
H - tadpole

(1cii)
E ; it is used for collecting insects

F ; it is used for collecting flying insects and other invertebrates from long grass

(1ciii)
(i)By wind

(1civ)
(i) presence of gills from respiration
(ii) presence of long muscular tail for swimming and movement in water
(iii) presence of transparent fin for swimming
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
(2ai)
I - Spirogyra
J - Okro fruit
K - mango fruit
L - Tick
M - Bean weevil

(2aii)
(i)their bodies are characterised by multicellular filaments
(ii)it is an unbranched, filamentous green algae occuring in stagnant water

(2bi)
Tabulate
-Under specimen J-
(i)seed are small
(ii)many seeded
(iii)anile placentation

-Under specimen K-
(i)seed in large
(ii)one seeded
(iii)Basal placentation

(2bii)
L - class arachnid
M - class insect

(2biii)
L; cause stress in animals affected by bites, blood losses that can lead to anemia and even death

M; they make holes in the plants to oviposition the causing directed and indirect damage

(2ci)
Diagram of specimen K


(2cii)
Tabulate
-Under specimen L-
(i)pear shaped body
(ii)approximately 3 to 5 mm in length to age, species

-Under specimen M-
(i)general compact and oral in shape
(ii)size range from 1 to 22mm
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
(3ai)
N - cactus plant
O - water lettuce
P - soldier termite

(3aii)
N - Terrestrial habitat/forest
O - Aquatic habitat
P - Terrestrial habitat

(3bi)
Adaptive features of N (cactus)
(i)presence of spines to reduce water loss
(ii)presence of succulent stems to conserve water.
(iii)present of thick and waxy skin to reduce loss of water

Adoptive features of O (water lettuce)
(i)presence of air space for bouyancy
(ii)presence of numerous root or absorption of mineral salt
(iii)presence of more stomata on upper surface for diffusion of CO

(3bii)
Diagram of specimen P


(3ci)
(i)it increases humus content of the soil
(ii)it increases penetration of water in the soil by burrowing

(3cii)
(i)defending the colony against enemies
COMPLETED
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같

Offline chance

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Re: Neco practical biology answer 2021/2022
« Reply #2 on: July 22, 2021, 01:43:06 pm »
The biology diagram

Offline NORTOLA

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Re: Neco practical biology answer 2021/2022
« Reply #3 on: July 28, 2021, 08:47:03 am »
COMPLETED


Completed
CHEMISTRY-OBJ
1EECBBAEBBB
11DDDBEAEABB
21DBECCDAAAB
31BADCBACDAC
41CECCEADBDC
51CEBEEDDBAE
Completed!.
====================================
CHEMISTRY-THEORY
(1ai)
(i) Base has bitter taste
(ii) Base is soapy to touch
(iii) Base turns litmus paper blue

(1aii)
The steps involved are:
(i)Shift conversion
(ii)Removal of carbon (iv) oxide
(iii)Steam reforming

(1aiii)
Cracking is the process by which heavier hydrocarbon molecule is splitted into two or more lighter molecules

(1aiv)
Thermal cracking

(1bi)
P ion = 1s2s2p⁶

(1bii)
Formula of chloride is Pcl2

(1biii)
Reducing agent
This is because it undergoes oxidation by losing electrons

(1ci)
Electron affinity is the energy released when a gaseous atom gains an electron to form a gaseous negative ion.

(1cii)
This is because it has lone pairs of electrons

(1di)
(i) By adding a catalyst

(ii) FeS(s) + 2HCl(g) -----> FeCl(g) + H2S(s)

Xg = ?
No. of FeCl2 = 127g/mole
No. of FeS= 88g/mole

Mole = Mass/ No. of Mass = 3.2/127 = 0.025mole of FeCl2

By comparison,
1 mole of FeS = 1 mole of FeCl2
X moles of FeS = 0.025 of FeCl2
X = 0.025mole of FeS

Recall,
Mass = Mole * molar mass
Mass = 0.025*88
Mass = 2.2g of FeS
X = 2.2g

(1dii)
(i)Chlorofluorocarbons
(ii)Ammonia
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
(4a)
(i)Enthalpy of combustion can be defined as the amount of heat evolved when one mole of a substance burns in air or oxygen

(ii) Isomerism can be defined as a phenomenon in which organic compounds are having the same molecular formula but different structural formula

(4bi)
NO2 - Acidic oxide
CO - Neutral oxide
Fe2O3 - Basic oxide
Al2O3 - Amphoteric oxide

(4bii)
(i)Nitrous oxide
(ii)Carbon (iv) oxide

(4c)
(i) Fractional distillation of liquid air

(ii) 2KNO3 -----> 2KNO2(s) + O2(g)

(NH)CO3(s) ------>2NH3(g) + CO2(g) + H2O(g)

(iii) No. of molecules = 4/16 6.02 10껙
= 1.5 10껙

(4di)
(i)Sodium
(ii)Potassium

(4dii)
(i)Carbon (iv) oxide
(ii)Carbon

(4diii)
(i)Hydration
(ii)Oxidation
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같

(3a)
(i) Iron (Fe)
(ii) Fe3C4
(iii)
- chlorine displace bromine
- The displaced bromine gives the reddish brown colour
(iv) 2KBr(aq) + Cl2(g) ----> 2KCl(aq) + Br2(l)

(3b)
(i)
- Cement industries
- Glass industries
(ii) Quick lime
(iii) TABULATE PLS
=>Salt to be prepared<=
- KNO3
- CaCl2
- FeCl3
- CuSO4
- PbSO4

=>Starting material<=
- KOH
- CaCO3
- Fe(s)
- CuO
- Pb(NO3)2

=>Method of preparation<=
- Neutralization
- Dilute acid and trioxocarbonate (iv)
- Combination of constituent elements
- Dilute acid and insoluble base
- Double decomposition

(3c)
(i) By burning sulphur in dry air
(ii) 2SO2(aq) + O2(g) ------> 2SO3(aq) + heat

(iii)
- Combining sulphur (iv) oxide with oxygen in excess to firm sulphur (vi) oxide
- Cooling and passing the SO3 formed through and absorption tower to produce the acid

(d)
(i) 2*9600C produces 119g
(1.5*2*3600)C produces xg
x= 1.5*2*3600*119/2*96500
x= 6.66grams

(ii) Strong electrolyte conducts large currents WHILE Weak electrolyte do not conduct electricity readily
====================================

(6ai)
Diagram


(6aii)
Vanadium (v) oxide : It enables equilibrium equilibrium to be reached in a shorter time

(6b)
(i) Caustic soda solution
(ii) Pure Alumina in molten cryolite
(iii) Graphite rods: Oxygen is given off at the anode, slowing burning away the anode as CO2

(6c)
(i)
- Dilute acids have a sour taste
- Acids turn blue litmus red
- Concentrated forms of strong acids are corrosive

(ii) HCl will have a larger electrical conductivity because it ionizes completely in water to give hydrogen ions with concentration very high

(iii)
(i) As an acid with bases
NaCl(aq) + HNO3(aq) ---> NaNO3(aq) + H2O(l)

(ii) H2S(g) + 2HNO3(aq) ----> S(s) + 2H2O(l) + 2NO2(g)
Completed
같같같같같같같같같같

Offline NORTOLA

  • VIP MEMBER
  • Peace Member
  • *
  • Posts: 138
  • Vote for me: +31/-4
  • Location: Akwa ibom state
Re: Neco practical biology answer 2021/2022
« Reply #4 on: July 28, 2021, 08:51:04 am »
COMPLETED


Completed
CHEMISTRY-OBJ
1EECBBAEBBB
11DDDBEAEABB
21DBECCDAAAB
31BADCBACDAC
41CECCEADBDC
51CEBEEDDBAE
Completed!.
====================================
CHEMISTRY-THEORY
(1ai)
(i) Base has bitter taste
(ii) Base is soapy to touch
(iii) Base turns litmus paper blue

(1aii)
The steps involved are:
(i)Shift conversion
(ii)Removal of carbon (iv) oxide
(iii)Steam reforming

(1aiii)
Cracking is the process by which heavier hydrocarbon molecule is splitted into two or more lighter molecules

(1aiv)
Thermal cracking

(1bi)
P ion = 1s2s2p⁶

(1bii)
Formula of chloride is Pcl2

(1biii)
Reducing agent
This is because it undergoes oxidation by losing electrons

(1ci)
Electron affinity is the energy released when a gaseous atom gains an electron to form a gaseous negative ion.

(1cii)
This is because it has lone pairs of electrons

(1di)
(i) By adding a catalyst

(ii) FeS(s) + 2HCl(g) -----> FeCl(g) + H2S(s)

Xg = ?
No. of FeCl2 = 127g/mole
No. of FeS= 88g/mole

Mole = Mass/ No. of Mass = 3.2/127 = 0.025mole of FeCl2

By comparison,
1 mole of FeS = 1 mole of FeCl2
X moles of FeS = 0.025 of FeCl2
X = 0.025mole of FeS

Recall,
Mass = Mole * molar mass
Mass = 0.025*88
Mass = 2.2g of FeS
X = 2.2g

(1dii)
(i)Chlorofluorocarbons
(ii)Ammonia
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같
(4a)
(i)Enthalpy of combustion can be defined as the amount of heat evolved when one mole of a substance burns in air or oxygen

(ii) Isomerism can be defined as a phenomenon in which organic compounds are having the same molecular formula but different structural formula

(4bi)
NO2 - Acidic oxide
CO - Neutral oxide
Fe2O3 - Basic oxide
Al2O3 - Amphoteric oxide

(4bii)
(i)Nitrous oxide
(ii)Carbon (iv) oxide

(4c)
(i) Fractional distillation of liquid air

(ii) 2KNO3 -----> 2KNO2(s) + O2(g)

(NH)CO3(s) ------>2NH3(g) + CO2(g) + H2O(g)

(iii) No. of molecules = 4/16 6.02 10껙
= 1.5 10껙

(4di)
(i)Sodium
(ii)Potassium

(4dii)
(i)Carbon (iv) oxide
(ii)Carbon

(4diii)
(i)Hydration
(ii)Oxidation
같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같같′같같같같같같같

(3a)
(i) Iron (Fe)
(ii) Fe3C4
(iii)
- chlorine displace bromine
- The displaced bromine gives the reddish brown colour
(iv) 2KBr(aq) + Cl2(g) ----> 2KCl(aq) + Br2(l)

(3b)
(i)
- Cement industries
- Glass industries
(ii) Quick lime
(iii) TABULATE PLS
=>Salt to be prepared<=
- KNO3
- CaCl2
- FeCl3
- CuSO4
- PbSO4

=>Starting material<=
- KOH
- CaCO3
- Fe(s)
- CuO
- Pb(NO3)2

=>Method of preparation<=
- Neutralization
- Dilute acid and trioxocarbonate (iv)
- Combination of constituent elements
- Dilute acid and insoluble base
- Double decomposition

(3c)
(i) By burning sulphur in dry air
(ii) 2SO2(aq) + O2(g) ------> 2SO3(aq) + heat

(iii)
- Combining sulphur (iv) oxide with oxygen in excess to firm sulphur (vi) oxide
- Cooling and passing the SO3 formed through and absorption tower to produce the acid

(d)
(i) 2*9600C produces 119g
(1.5*2*3600)C produces xg
x= 1.5*2*3600*119/2*96500
x= 6.66grams

(ii) Strong electrolyte conducts large currents WHILE Weak electrolyte do not conduct electricity readily
====================================

(6ai)
Diagram


(6aii)
Vanadium (v) oxide : It enables equilibrium equilibrium to be reached in a shorter time

(6b)
(i) Caustic soda solution
(ii) Pure Alumina in molten cryolite
(iii) Graphite rods: Oxygen is given off at the anode, slowing burning away the anode as CO2

(6c)
(i)
- Dilute acids have a sour taste
- Acids turn blue litmus red
- Concentrated forms of strong acids are corrosive

(ii) HCl will have a larger electrical conductivity because it ionizes completely in water to give hydrogen ions with concentration very high

(iii)
(i) As an acid with bases
NaCl(aq) + HNO3(aq) ---> NaNO3(aq) + H2O(l)

(ii) H2S(g) + 2HNO3(aq) ----> S(s) + 2H2O(l) + 2NO2(g)
Completed
같같같같같같같같같같

 

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