COMPLETED
Completed
CHEMISTRY-OBJ
1EECBBAEBBB
11DDDBEAEABB
21DBECCDAAAB
31BADCBACDAC
41CECCEADBDC
51CEBEEDDBAE
Completed!.
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CHEMISTRY-THEORY
(1ai)
(i) Base has bitter taste
(ii) Base is soapy to touch
(iii) Base turns litmus paper blue
(1aii)
The steps involved are:
(i)Shift conversion
(ii)Removal of carbon (iv) oxide
(iii)Steam reforming
(1aiii)
Cracking is the process by which heavier hydrocarbon molecule is splitted into two or more lighter molecules
(1aiv)
Thermal cracking
(1bi)
P ion = 1s²2s²2p⁶
(1bii)
Formula of chloride is Pcl2
(1biii)
Reducing agent
This is because it undergoes oxidation by losing electrons
(1ci)
Electron affinity is the energy released when a gaseous atom gains an electron to form a gaseous negative ion.
(1cii)
This is because it has lone pairs of electrons
(1di)
(i) By adding a catalyst
(ii) FeS(s) + 2HCl(g) -----> FeCl(g) + H2S(s)
Xg = ?
No. of FeCl2 = 127g/mole
No. of FeS= 88g/mole
Mole = Mass/ No. of Mass = 3.2/127 = 0.025mole of FeCl2
By comparison,
1 mole of FeS = 1 mole of FeCl2
X moles of FeS = 0.025 of FeCl2
X = 0.025mole of FeS
Recall,
Mass = Mole * molar mass
Mass = 0.025*88
Mass = 2.2g of FeS
X = 2.2g
(1dii)
(i)Chlorofluorocarbons
(ii)Ammonia
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(4a)
(i)Enthalpy of combustion can be defined as the amount of heat evolved when one mole of a substance burns in air or oxygen
(ii) Isomerism can be defined as a phenomenon in which organic compounds are having the same molecular formula but different structural formula
(4bi)
NO2 - Acidic oxide
CO - Neutral oxide
Fe2O3 - Basic oxide
Al2O3 - Amphoteric oxide
(4bii)
(i)Nitrous oxide
(ii)Carbon (iv) oxide
(4c)
(i) Fractional distillation of liquid air
(ii) 2KNO3 -----> 2KNO2(s) + O2(g)
(NH)CO3(s) ------>2NH3(g) + CO2(g) + H2O(g)
(iii) No. of molecules = 4/16 × 6.02 × 10²³
= 1.5 × 10²³
(4di)
(i)Sodium
(ii)Potassium
(4dii)
(i)Carbon (iv) oxide
(ii)Carbon
(4diii)
(i)Hydration
(ii)Oxidation
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(3a)
(i) Iron (Fe)
(ii) Fe3C4
(iii)
- chlorine displace bromine
- The displaced bromine gives the reddish brown colour
(iv) 2KBr(aq) + Cl2(g) ----> 2KCl(aq) + Br2(l)
(3b)
(i)
- Cement industries
- Glass industries
(ii) Quick lime
(iii) TABULATE PLS
=>Salt to be prepared<=
- KNO3
- CaCl2
- FeCl3
- CuSO4
- PbSO4
=>Starting material<=
- KOH
- CaCO3
- Fe(s)
- CuO
- Pb(NO3)2
=>Method of preparation<=
- Neutralization
- Dilute acid and trioxocarbonate (iv)
- Combination of constituent elements
- Dilute acid and insoluble base
- Double decomposition
(3c)
(i) By burning sulphur in dry air
(ii) 2SO2(aq) + O2(g) ------> 2SO3(aq) + heat
(iii)
- Combining sulphur (iv) oxide with oxygen in excess to firm sulphur (vi) oxide
- Cooling and passing the SO3 formed through and absorption tower to produce the acid
(d)
(i) 2*9600C produces 119g
(1.5*2*3600)C produces xg
x= 1.5*2*3600*119/2*96500
x= 6.66grams
(ii) Strong electrolyte conducts large currents WHILE Weak electrolyte do not conduct electricity readily
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(6ai)
Diagram
(6aii)
Vanadium (v) oxide : It enables equilibrium equilibrium to be reached in a shorter time
(6b)
(i) Caustic soda solution
(ii) Pure Alumina in molten cryolite
(iii) Graphite rods: Oxygen is given off at the anode, slowing burning away the anode as CO2
(6c)
(i)
- Dilute acids have a sour taste
- Acids turn blue litmus red
- Concentrated forms of strong acids are corrosive
(ii) HCl will have a larger electrical conductivity because it ionizes completely in water to give hydrogen ions with concentration very high
(iii)
(i) As an acid with bases
NaCl(aq) + HNO3(aq) ---> NaNO3(aq) + H2O(l)
(ii) H2S(g) + 2HNO3(aq) ----> S(s) + 2H2O(l) + 2NO2(g)
Completed
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