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Author Topic: NECO GCE 2013/2014 Physics Paper II Objective and Essay/Theory Questions And Answers  (Read 3478 times)

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Offline MEGAX

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NECO GCE 2013/2014 Confirmed Physics Paper I & II (Objective and Essay) Questions And Answers

NOTE: The Below Answers was posted @ EarlyFace Examination Room for Only Our Subscribers before The Exam start. You must first Register Or Login as an EarlyFace member to be able to gain access any of the Links in Order to get this 2013/2014 Real NECO GCE Questions And Answers. Or pay For it..

LINK1: http://www.earlyface.com.ng/index.php?action=ezportal;sa=page;p=4

LINK2: http://www.earlyface.com.ng/index.php?action=ezportal;sa=page;p=10



Verified NECO PHYSICS OBJ:
1-10: EEBEACBDDA
11-20: DADBDECDED
21-30: AEDBCBBBDA
31-40: BDBBCDEBBB
41-50: DBCACBEACC
51-60: CADCDEECCE


ESSAY/THEORY:
========================
^ means Raise to power.
(alpha) means an Alpha sign(i guess u knw it).
tita Means a Tita  sign(i guess u knw tita sign dat looks like zero).
Squar root looks like dis _/
IN NO13, ^ Means Landa sign(It looks like Y upside dwn)
Eg: V=fLanda
Speed (v) = f^means =fLanda
========================

(2ai)
it rests on its base
it rests on its vertex
(2b)
Potential energy remains constant ie p>E=0 at neutral equilibrium and potential energy increases when it is unstable equilibrium.

(4a)
-table knife
-sugarstong
-fishing rod
(4b)
This occurs when there is no friction

(3)
Area of expansivity(beta)=2alpha
beta=2alpha
beta=A2-A1/A1*change in tita
2alpha=B-A/A(80-20)
2alpha=B-A/60A
120A*alpha=B-A
B=120A*alpha+A
B=A(1+120alpha)
B/A=1+120alpha

(9a)
Work function is the energy required for the electrons to be emitted from the surface of a metal when light of sufficient of amount of energy is incident on it
(9b) It is used to examine cancerous cells in humans

(11a)
(i) Force - its unit is newton (N)
(ii)
- it causes the object to accelerate.
- it causes the object to change direction.
(11b)
(C)^2 = (A)^2 + (B)^2
(11ci)
This is because the motion is under the combined effect of vertical and horizontal forces
(11cii) Missile, Bombs
(11ciii)

(11Civ)
Hmax = (u^2)(sin^2)tita/2g
Hmax = u^2sin^2tita?2 * 10 = u^2sin^2tita/ 20
Hmax = u^2(sin45)^2/20 = u^2 * 0.5 / 20
Hmax = 0.025u^2
(11Cv) Rmax = u^2/2g
1000 = u^2/ 2*10
u^2 = 1000 *2*10
u^2 = 20,000
u = square root of (2000) = 141.42m/s

(12a)
(i)principle of linear conservation of linear momentum states that in an isolated system,the total momentum after collision is equal to the total momentum before collision
(ii)the initial momentum of the gun is 0 and the final momentum of the gun is -m1v1+m2v2
Total momentum before collision=total momentum after collision
0=-m1v1+m2v2
mivi=m2v2

(12b)water when heated from -15 degree celcius to 80 degree celcius will change the water from low temperature to higher temperature and its volume increases but for alcohol,its temperature decreases but its volume increases because of thermal capacity.

(12ci)area of coin(A)=pie*r^2
=22l7*1.4*10^-2
=4.4*10^-2
beta=2alpha, beta=2*1.7*10^-5k^-1
beta=A2-A1/A1*change in tita
53.4*10^-5=(1.7*10^-5)/(4.4*10^-2*change in tita)
53.4*10^-5*4.4*10^-2*change in tita=1.7*10^-5
change in tita=1.7*10^-5/(3.4*10^-5*4.4*10^-2)
change in tita=0.1136*10^(-5+7)/14.96*10^-7
change in tita=1.14*10^-1*10^2
change in tita=1.14*10
change in tita=11.4k
(iii)
3.4*10^-5=change in A/4.4*10^-2*90
change in A=3.4*10^-5*4.4*10^-2*90
change in A=1.35*10^3*10^-7
change in A=1.35*10^-4m^2

(13a)
-Temperature
- Density
(13b)
Refractive index = sini^0/ sinr^0
(13ci) - it helps to receive light sensitive source.
(13cii) it helps in forming the real the image.
(13ciii) it helps in formation of the image
(13di) Lenght (L) = 0.5cm
Mass per unit lenght = 4*10^-4kgm^-1
Mass (M) = 2.5kg
Speed (v) = f^
T = mg = 2.5 * 10 = 25N
V = Square root of (T/M)
V = Square root of (25/4 * 10^-1) = square root of (6.25 * 10 ^-4)
V = square root of (62500) = 250m/s
(13dii) L = ^/2 + ^/2 +=2^/2 = ^
V = F^
250 = 0.5 * F
F = 250/ 0.5 = 500HZ

   
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